9/4+(3/4x+2)^2=0

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Solution for 9/4+(3/4x+2)^2=0 equation: 


x in (-oo:+oo)

((3/4)*x+2)^2+9/4 = 0

(3/4*x+2)^2+9/4 = 0

(4*(3/4*x+2)^2)/4+9/4 = 0

4*(3/4*x+2)^2+9 = 0

9/4*x^2+12*x+25 = 0

9/4*x^2+12*x+25 = 0

9/4*x^2+12*x+25 = 0

DELTA = 12^2-(9/4*4*25)

DELTA = -81

DELTA < 0

1 = 0

1/4 = 0

1/4 = 0 // * 4

1 = 0

x belongs to the empty set

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